AP EAMCET · PHYSICS · Rotational Motion
The angular velocity of a body changes from \(6 \mathrm{rad} \mathrm{s}^{-1}\) to \(21 \mathrm{rad} \mathrm{s}^{-1}\) in a time of 1.5 s. If the moment of inertia of the body is \(100 \mathrm{~g} \mathrm{~m}^2\), then the rate of change of angular momentum of the body is
- A 0.12 N m
- B 0.6 N m
- C 1 N m
- D 0.8 N m
Answer & Solution
Correct Answer
(C) 1 N m
Step-by-step Solution
Detailed explanation
\(I = 100 \, \mathrm{g} \, \mathrm{m}^2 = 0.1 \, \mathrm{kg} \, \mathrm{m}^2\) \(\frac{\Delta L}{\Delta t} = I \frac{\Delta \omega}{\Delta t} = 0.1 \, \mathrm{kg} \, \mathrm{m}^2 \times \frac{(21 - 6) \, \mathrm{rad} \, \mathrm{s}^{-1}}{1.5 \, \mathrm{s}}\)…
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