AP EAMCET · Chemistry · General Principles and Processes of Isolation of Metals
In the following unbalanced reaction, the product formed is
\(\mathrm{Al}_2 \mathrm{O}_3+\mathrm{NaOH}(a q)+\mathrm{H}_2 \mathrm{O} \longrightarrow\)
- A \(\mathrm{Na}_3\left[\mathrm{Al}(\mathrm{OH})_6\right]\)
- B \(\mathrm{Na}_3\left[\mathrm{Al}(\mathrm{OH})_4\right]\)
- C \(\mathrm{Na}_2\left[\mathrm{Al}(\mathrm{OH})_5\right]\)
- D \(\mathrm{Na}\left[\mathrm{Al}(\mathrm{OH})_6\right]\)
Answer & Solution
Correct Answer
(A) \(\mathrm{Na}_3\left[\mathrm{Al}(\mathrm{OH})_6\right]\)
Step-by-step Solution
Detailed explanation
Aluminium oxide reacts with aqueous solution of sodium hydroxide to form sodium hexahydroxyaluminate (III). \(\mathrm{Al}_2 \mathrm{O}_3+\mathrm{NaOH}+\mathrm{H}_2 \mathrm{O} \longrightarrow \mathrm{Na}_3\left[\mathrm{Al}(\mathrm{OH})_6\right]\)
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