AP EAMCET · Chemistry · Surface Chemistry

In an adsorption experiment, a graph between $\log (x / m)$ versus $logP$ was found to be linear with a slope of $45 °$ . The intercept on $\log (x / m)$ axis was found to be $0.3010$ . The amount of gas adsorbed per gram of charcoal under a pressure of $0.5 atm$ is

A $0.5 g$
B $1.0 g$
C $1.5 g$
D $0.75 g$

Verified Solution

Answer & Solution

Correct Answer

(B) $1.0 g$

Step-by-step Solution

Detailed explanation

According to the Freundlich's Adsorption Isotherm, xm=k·p1/n By taking the log both sides, logxm=logk+1nlogp So, slope =1n⇒tan45°=1(n=1) logK=0.3010⇒k=2 xm=2(0.5)1n xm=1 Hence, the amount of gas adsorbed per gram of charcoal under a pressure of 0.5 atm…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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In an adsorption experiment, a graph between log(x/m) versus logP was found to be linear with a slope of 45°. The intercept on log(x/m) axis was found to be 0.3010. The amount of gas adsorbed per gram of charcoal under a pressure of 0.5 atm is

Step-by-step Solution

In an adsorption experiment, a graph between $\log (x / m)$ versus $logP$ was found to be linear with a slope of $45 °$ . The intercept on $\log (x / m)$ axis was found to be $0.3010$ . The amount of gas adsorbed per gram of charcoal under a pressure of $0.5 atm$ is