AP EAMCET · Chemistry · Structure of Atom
If the uncertainty in velocity of electron \((\Delta \mathrm{v})\) is \(0.1 \mathrm{~m} / \mathrm{s}\), the uncertainty in its position \((\Delta x)\) is
(given: \(m_e=9.1 \times 10^{-31} \mathrm{~kg}\) )
- A \(2.02 \times 10^{-4} \mathrm{~m}\)
- B \(4.04 \times 10^{-4} \mathrm{~m}\)
- C \(5.79 \times 10^{-4} \mathrm{~m}\)
- D \(8.42 \times 10^{-4} \mathrm{~m}\)
Answer & Solution
Correct Answer
(C) \(5.79 \times 10^{-4} \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
\(\Delta x \cdot \Delta \mathrm{P}=\Delta \mathrm{x} \cdot \mathrm{m} \Delta \mathrm{v}=\frac{\mathrm{h}}{4 \pi}=\frac{6.626 \times 10^{-34}}{4 \times 3.14}\)…
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