AP EAMCET · Maths · Statistics
The mean of 5 observations is 4.4 and their variance is 8.24. If three of those observations are 1,2 and 6 , then the other two observations are
- A 9,4
- B 9,5
- C 9,2
- D 9,13
Answer & Solution
Correct Answer
(A) 9,4
Step-by-step Solution
Detailed explanation
Let other two observation be \(x\) and \(y\) \(4.4=\frac{1+2+6+x+y}{5} \Rightarrow x+y=13...(i)\) and \(8.24=\frac{1}{5}\left(1^2+2^2+6^2+x^2+y^2\right)-(4.4)^2\) \(\Rightarrow x^2+y^2=97\) Now, \(x^2+y^2=\frac{(x+y)^2+(x-y)^2}{2}\)…
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