AP EAMCET · PHYSICS · Center of Mass Momentum and Collision
A ball is thrown vertically down from a height of \(40 \mathrm{~m}\) from the ground with an initial velocity \(v\). The ball hits the ground, loses \(\frac{1}{3}\) rd of its total mechanical energy and rebounds back to the same height. If the acceleration due to gravity is \(10 \mathrm{~ms}^{-2}\), then the value of \(v\) is
- A \(5 \mathrm{~ms}^{-1}\)
- B \(10 \mathrm{~ms}^{-1}\)
- C \(15 \mathrm{~ms}^{-1}\)
- D \(20 \mathrm{~ms}^{-1}\)
Answer & Solution
Correct Answer
(D) \(20 \mathrm{~ms}^{-1}\)
Step-by-step Solution
Detailed explanation
As per question, the ball hits the ground loses \(\frac{1}{3} \mathrm{rd}\) of its total mechanical energy and rebounds back to the same height.…
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