AP EAMCET · Chemistry · Thermodynamics (C)
If the standard enthalpy change \(\left(\Delta_{\mathrm{r}} \mathrm{H}^\theta\right)\) for reaction \(\mathrm{H}_2(\mathrm{~g})+\mathrm{Br}_2(\mathrm{l}) \rightarrow 2 \mathrm{HBr}(\mathrm{g})\) is \(-72.8 \mathrm{~kJ}\), the standard enthalpy of formation \(\left(\Delta_{\mathrm{f}} \mathrm{H}^\theta\right)\) of \(\mathrm{HBr}(\mathrm{g})\) (in \(\left.\mathrm{kJ} \mathrm{mol}^{-1}\right)\) is
- A -36.4
- B 36.4
- C -18.2
- D -18.2
Answer & Solution
Correct Answer
(A) -36.4
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { } \Delta \mathrm{H}_{\mathrm{f}}^{\circ}\left(\mathrm{H}_2 \text { gas }\right)=0.0 \mathrm{~kJ} \mathrm{~mol}^{-1}, \Delta \mathrm{H}_{\mathrm{f}}^{\circ}\left(\mathrm{Br}_2 \text { liquid) }\right. \\ & =0.0 \mathrm{~kJ} \mathrm{~mol}^{-1} \\ & \Delta…
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