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AP EAMCET · Chemistry · Coordination Compounds

Oxidation number of \(\mathrm{Cr}\) in \(\left[\mathrm{Cr}(\mathrm{CO})_6\right]\) is

  1. A 6
  2. B -6
  3. C 3
  4. D 0
Verified Solution

Answer & Solution

Correct Answer

(D) 0

Step-by-step Solution

Detailed explanation

CO (carbonyl) is a neutral ligand. So, oxidation number of the metal is metal carbonyl compounds will be 0 (zero). \(\left[\stackrel{0}{\mathrm{Cr}(\mathrm{CO})_6}\right] \text { : Hexacarbonyl chromium (0). }\)