AP EAMCET · Chemistry · Chemical Kinetics
At \(T(\mathrm{~K})\) if the rate constant for a zero order reaction is \(2.5 \times 10^{-3} \mathrm{~ms}^{-1}\), the time required for the initial concentration of reactant, \(R\) to fall from \(0.10 \mathrm{M}\) to \(0.075 \mathrm{M}\) at the same temperature in seconds is
- A 25
- B 5
- C 10
- D 20
Answer & Solution
Correct Answer
(C) 10
Step-by-step Solution
Detailed explanation
\(\begin{aligned} t & =\frac{\left[R_0\right]-[R]_E}{K} \quad t=\frac{0.1-0.075}{2.5 \times 10^{-3}} \\ & =\frac{0.025}{2.5 \times 10^{-3}} t=0.01 \times 10^3=10 \mathrm{~s}\end{aligned}\)
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