AP EAMCET · Chemistry · Structure of Atom
Which one of the following transitions of an electron in hydrogen atom emits radiation of the lowest wavelength?
- A \(n_2=\infty\) to \(n_1=2\)
- B \(n_2=4\) to \(n_1=3\)
- C \(n_2=2\) to \(n_1=1\)
- D \(n_2=5\) to \(n_1=3\)
Answer & Solution
Correct Answer
(C) \(n_2=2\) to \(n_1=1\)
Step-by-step Solution
Detailed explanation
As the value of \(n\) increases, the difference of energy between successive orbits decreases, ie, \(E_2-E_1>E_3-E_2>E_4-E_3 \text { and so on... }\) \(\because \quad \Delta E=\frac{h c}{\lambda}\) \(\therefore \lambda\) is lowest for \(n_2=2\) to \(n_1=1\) transition.
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