AP EAMCET · Maths · Circle
The length of the common chord of the circles and is
- A
- B
- C
- D
Answer & Solution
Correct Answer
(D)
Step-by-step Solution
Detailed explanation
S≡x2+y2+3x+5y+4=0 and S'≡x2+y2+5x+3y+4=0 Equation of common chord is S-S'=0 ⇒-2x+2y=0 ⇒x-y=0 Centre of S=0 is C-32,-52 Radius, r=94+254-4=92 p= length of the perpendicular from C on AB=-32+521+1=12 AB=length of common chord=2r2-p2=292-12=24=4
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