AP EAMCET · Chemistry · Ionic Equilibrium
If the ionization constant of hypochlorous acid (HOCl) is \(2.5 \times 10^{-5}\), the pH of \(1.0 \mathrm{M}\) of its solution is \((\log 5=0.7)\)
- A 3.3
- B 2.3
- C 4.3
- D 3
Answer & Solution
Correct Answer
(B) 2.3
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { Given, ionisation constant }\left(K_a\right)=2.5 \times 10^{-5} \\ & \text { and molarity }(c)=1.0 \mathrm{M} \\ & \because K_a=C \alpha^2 \\ & \qquad \begin{aligned} \therefore & =\sqrt{\frac{K_a}{C}}=\sqrt{\frac{2.5 \times 10^{-5}}{1}} \\ & =0.5…
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