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AP EAMCET · Chemistry · Thermodynamics (C)

Observe the following reaction
\(2 \mathrm{~A}_2(\mathrm{~g})+\mathrm{B}_2(\mathrm{~g}) \xrightarrow{\mathrm{T}(\mathrm{K})} 2 \mathrm{~A}_2 \mathrm{~B}(\mathrm{~g})+600 \mathrm{~kJ}\)
The standard enthalpy of formation \(\left(\Delta_{\mathrm{f}} \mathrm{H}^{\prime}\right)\) of \(\mathrm{A}_2 \mathrm{~B}(\mathrm{~g})\) is

  1. A \(600 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
  2. B \(300 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
  3. C \(-300 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
  4. D Missing
Verified Solution

Answer & Solution

Correct Answer

(C) \(-300 \mathrm{~kJ} \mathrm{~mol}^{-1}\)

Step-by-step Solution

Detailed explanation

Given reaction \(-2 \mathrm{~A}_2+\mathrm{B}_2 \rightarrow 2 \mathrm{~A}_2 \mathrm{~B}+600 \mathrm{~kJ}\) By this equation indicates that the formation of 2 moles of \(\mathrm{A}_2 \mathrm{~B}\) releases 600 kJ energy.…