AP EAMCET · Chemistry · Chemical Equilibrium
At \(1000 \mathrm{~K}\), if the equilibrium constant \(K_p\) for the reaction.
\(2 \mathrm{NOCl}(g) \rightleftharpoons 2 \mathrm{NO}(g)+\mathrm{Cl}_2(g)\)
is \(4.157 \times 10^{-4}\) bar, the \(K_C\left(\right.\) in \(\mathrm{mol} \mathrm{L}^{-1}\) ) is \(\left(R=0.083 \mathrm{~L} \mathrm{bar} \mathrm{K}^{-1} \mathrm{~mol}^{-1}\right)\)
- A \(4.16 \times 10^{-7}\)
- B \(4.16 \times 10^{-4}\)
- C \(50 \times 10^{-4}\)
- D \(50 \times 10^{-6}\)
Answer & Solution
Correct Answer
(D) \(50 \times 10^{-6}\)
Step-by-step Solution
Detailed explanation
\(K_p=K_c(R T)^{\Delta n}\) Where, \(\begin{aligned} & K_C \text { and } K_p=\text { Equilibrium constants } \\ & R=\text { Gas constant }\left(0.083 \mathrm{~L} \mathrm{bar}^{-1} \times \mathrm{mol}^{-1}\right) \\ & T=\text { Temperature }(1000 \mathrm{~K}) \end{aligned}\)…
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