AP EAMCET · Chemistry · Structure of Atom
Calculate the wave number and frequency of orange radiation having wavelength \(6300 Å\).
- A \(1.587 \times 10^8 \mathrm{~m}^{-1}, 4.761 \times 10^{16} \mathrm{~s}^{-1}\)
- B \(1.587 \times 10^4 \mathrm{~m}^{-1}, 4.761 \times 10^{14} \mathrm{~s}^{-1}\)
- C \(1.587 \times 10^6 \mathrm{~m}^{-1}, 4.761 \times 10^{14} \mathrm{~s}^{-1}\)
- D \(1.587 \times 10^6 \mathrm{~m}^{-1}, 4.761 \times 10^{16} \mathrm{~s}^{-1}\)
Answer & Solution
Correct Answer
(C) \(1.587 \times 10^6 \mathrm{~m}^{-1}, 4.761 \times 10^{14} \mathrm{~s}^{-1}\)
Step-by-step Solution
Detailed explanation
For orange radiation (EMR) of \(\lambda=6300 Å\) (i) Wave number, \(\bar{v}=\frac{1}{\lambda}=\frac{1}{6300 Å}=\frac{1}{6300 \times 10^{-10} \mathrm{~m}}\) \(=1.587 \times 10^6 \mathrm{~m}^{-1}\) (ii) Frequency,…
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