AP EAMCET · Chemistry · Classification of Elements and Periodicity in Properties
\(Assertion\) (A) Helium and beryllium have similar outer electronic configuration \(n s^2\).
\(Reason\) (R) Both are chemically inert
- A Both \((A)\) and \((R)\) are correct and \((R)\) is the correct explanation of \((A)\).
- B Both \(\mathrm{A}\) and \(\mathrm{R}\) are correct but \(\mathrm{R}\) is not the correct explanation of \(\mathrm{A}\).
- C \(A\) is correct but \(R\) is incorrect.
- D Both \(A\) and \(R\) are incorrect.
Answer & Solution
Correct Answer
(C) \(A\) is correct but \(R\) is incorrect.
Step-by-step Solution
Detailed explanation
The electronic configuration of \(\begin{aligned} \mathrm{He} & =1 s^2 \\ \mathrm{Be} & =1 s^2 2 s^2\end{aligned}\) Both have \(n s^2\) configuration but helium is inert because its only shell i.e. \(1 s\) is completely filled while Be is a reactive alkaline earth metal. So, A…
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