AP EAMCET · Chemistry · Chemical Bonding and Molecular Structure
Arrange the following molecules according to decreasing order of their \(\mathrm{O}-\mathrm{O}\) bond lengths.
- A \(\mathrm{O}_3>\mathrm{H}_2 \mathrm{O}_2>\mathrm{O}_2\)
- B \(\mathrm{H}_2 \mathrm{O}_2>\mathrm{O}_3>\mathrm{O}_2\)
- C \(\mathrm{O}_2>\mathrm{H}_2 \mathrm{O}_2>\mathrm{O}_3\)
- D \(\mathrm{O}_2>\mathrm{O}_3>\mathrm{H}_2 \mathrm{O}_2\)
Answer & Solution
Correct Answer
(B) \(\mathrm{H}_2 \mathrm{O}_2>\mathrm{O}_3>\mathrm{O}_2\)
Step-by-step Solution
Detailed explanation
\(\mathrm{H}_2 \mathrm{O}_2\) has only single bond with bond length \(1.41 Å\), \(\mathrm{O}_2\) has double bond with bond length \(1.33 Å\). \(\mathrm{O}_3\) has a partial double bond due to resonance of lone pairs of electrons. So, correct order is…
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More questions from Chemistry
- Calculate \(\Delta H\) in \(\mathrm{kJ}\) for the following reaction
\[
\mathrm{C}(\mathrm{g})+\mathrm{O}_2(\mathrm{~g}) \longrightarrow \mathrm{CO}_2(\mathrm{~g})
\]
Given that,
\[
\begin{gathered}
\mathrm{H}_2 \mathrm{O}(g)+\mathrm{C}(g) \longrightarrow \mathrm{CO}(g)+\mathrm{H}_2(g) ; \\
\Delta H=+131 \mathrm{~kJ} \\
\mathrm{CO}(g)+\frac{1}{2} \mathrm{O}_2(g) \longrightarrow \mathrm{CO}_2(g) ; \\
\Delta H=-282 \mathrm{~kJ} \\
\mathrm{H}_2(g)+\frac{1}{2} \mathrm{O}_2(g) \longrightarrow \mathrm{H}_2 \mathrm{O}(g) ; \\
\Delta H=-242 \mathrm{~kJ}
\end{gathered}
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