AP EAMCET · Maths · Straight Lines
The equation of the locus of points which are equidistant from the points \((2,3)\) and \((4,5)\) is
- A \(x+y=0\)
- B \(x+y=7\)
- C \(4 x+4 y=38\)
- D \(x+y=1\)
Answer & Solution
Correct Answer
(B) \(x+y=7\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { Let } P(x, y) \text { be equidistance from } A(2,3) \text { and } B(4,5) \\ & \Rightarrow(P A)^2=(P B)^2 \\ & \Rightarrow(x-2)^2+(y-3)^2=(x-4)^2+(y-5)^2 \\ & \Rightarrow \\ & x^2-4 x+4+y^2+9-6 y=x^2+16-8 x+y^2+25-10 y \\ & \Rightarrow 4 x+4 y=28…
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