AP EAMCET · Chemistry · d and f Block Elements

A purple colored compound of Manganese $(X)$ decomposes on heating to liberate oxygen and forms compounds of Manganese ( $Y$ and $Z$ ) compound $Z$ reacts with $KOH$ in presence of potassium nitrate to give compound $Y$ . Compounds $X, Y$ and $Z$ respectively are

A $X - {KMnO}_{4} Y - {Mn}_{2} O_{7} Z - {MnO}_{2}$
B $X - K_{2} {MnO}_{4} Y - {KMnO}_{4} Z - {Mn}_{2} O_{7}$
C $X - {KMnO}_{4} Y - K_{2} {MnO}_{4} Z - {MnO}_{2}$
D $X - {KMnO}_{4} Y - {MnO}_{2} Z - MnO$

Verified Solution

Answer & Solution

Correct Answer

(C) $X - {KMnO}_{4} Y - K_{2} {MnO}_{4} Z - {MnO}_{2}$

Step-by-step Solution

Detailed explanation

The compound X is KMnO4. It gives on heating the oxygen and K2MnO4 and MnO2. MnO2 formed the K2MnO4 on reaction with potassium hydroxide in presence of the potassium nitrate. KMnO4(X) →Heating K2MnO4(Y)+MnO2(Z) +O2 MnO2(Z) +KOH/KNO3→K2MnO4(Y)…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Which of the following sets are correctly matched?

Molecule	Number of lone pairs of electrons on central atom	Hybridization
I) $\mathrm{PCl}_3$	$1$	$\mathrm{sp}^3$
II) $\mathrm{SO}_2$	$1$	$\mathrm{sp}^2$
III) $\mathrm{SF}_4$	$1$	$\mathrm{sp}^3\mathrm{d}$
IV) $\mathrm{ClF}_3$	$2$	$\mathrm{sp}^3\mathrm{d}$

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Molecule	Number of lone pairs of electrons on central atom	Hybridization
I) \(\mathrm{PCl}_3\)	\(1\)	\(\mathrm{sp}^3\)
II) \(\mathrm{SO}_2\)	\(1\)	\(\mathrm{sp}^2\)
III) \(\mathrm{SF}_4\)	\(1\)	\(\mathrm{sp}^3\mathrm{d}\)
IV) \(\mathrm{ClF}_3\)	\(2\)	\(\mathrm{sp}^3\mathrm{d}\)

A purple colored compound of Manganese (X) decomposes on heating to liberate oxygen and forms compounds of Manganese ( Y and Z ) compound Z reacts with KOH in presence of potassium nitrate to give compound Y. Compounds X,Y and Z respectively are

Step-by-step Solution

A purple colored compound of Manganese $(X)$ decomposes on heating to liberate oxygen and forms compounds of Manganese ( $Y$ and $Z$ ) compound $Z$ reacts with $KOH$ in presence of potassium nitrate to give compound $Y$ . Compounds $X, Y$ and $Z$ respectively are