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AP EAMCET · PHYSICS · Kinetic Theory of Gases

Pressure of a gas of constant volume at \(20^{\circ} \mathrm{C}\) is \(90 \mathrm{~cm}\) of \(\mathrm{Hg}\). At what temperature the pressure would change to \(75 \mathrm{~cm}\) of \(\mathrm{Hg}\) ?

  1. A \(233.2^{\circ} \mathrm{C}\)
  2. B \(-28.8^{\circ} \mathrm{C}\)
  3. C \(-24.2^{\circ} \mathrm{C}\)
  4. D \(28.8^{\circ} \mathrm{C}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(-28.8^{\circ} \mathrm{C}\)

Step-by-step Solution

Detailed explanation

Given, \[ \begin{aligned} & T_1=(273+20) \mathrm{K}=293 \mathrm{~K} \\ & p_1=90 \mathrm{~cm} \text { of } \mathrm{Hg} \\ & p_2=75 \mathrm{~cm} \text { of } \mathrm{Hg} \end{aligned} \] Since, volume of the gas is constant. Hence, according to ideal gas equation,…
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