The conjugate base of \(\mathrm{NH}_4^{+}\)is

What are the formal charges on terminal oxygens of ozone molecule?

DDT is

In the given reactions, ' \(\mathrm{X}\) ' and ' \(\mathrm{Y}\) ' respectively are
\(\mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}_2 \mathrm{NH}_2 \stackrel{\mathrm{X}}{\longleftrightarrow} \mathrm{C}_6 \mathrm{H}_5 \mathrm{CONH}_2 \stackrel{\mathrm{Y}}{\longrightarrow} \mathrm{C}_6 \mathrm{H}_5 \mathrm{NH}_2\)

The structures of \(\mathrm{BCl}_3\) and \(\mathrm{BCl}_3 \cdot \mathrm{NH}_3\), respectively are

From the following data at \(25^{\circ} \mathrm{C}\), calculate the \(\Delta_{\mathrm{r}} \mathrm{H}^0\) for \(\mathrm{H}_2 \mathrm{O}(\mathrm{g}) \rightarrow 2 \mathrm{H}(\mathrm{g})+\mathrm{O}(\mathrm{g})\)
reaction: \(\Delta_{\mathrm{r}} \mathrm{H}^0\left(\mathrm{~kJ} \mathrm{~mol}^{-1}\right)\)
\[
\begin{array}{ll}
\frac{1}{2} \mathrm{H}_2(\mathrm{~g})+\frac{1}{2} \mathrm{O}_2(\mathrm{~g}) \rightarrow \mathrm{OH}(\mathrm{g}) & 42.09 \\
\mathrm{H}_2(\mathrm{~g})+\frac{1}{2} \mathrm{O}_2(\mathrm{~g}) \rightarrow \mathrm{H}_2 \mathrm{O}(\mathrm{g}) & -242 \\
\mathrm{H}_2(\mathrm{~g}) \rightarrow 2 \mathrm{H}(\mathrm{g}) & 436 \\
\mathrm{O}_2(\mathrm{~g}) \rightarrow 2 \mathrm{O}(\mathrm{g}) & 496
\end{array}
\]

Calamine, bauxite, malachite and siderite respectively are ores of .........

The lengths of the sides of the rectangle of greatest area that can be inscribed in the ellipse \(x^2+4 y^2=64\) are

\(f(x)=\left\{\begin{array}{l}x^2, 0 \leq x < 1 \\ \sqrt{x}, 1 \leq x \leq 2\end{array} \Rightarrow \int_0^2 f(x) d x=\right.\)

\(\int \frac{\sin (x-a)}{\sin (x-b)} d x=A x+B \log |\sin (x-b)|+C \Rightarrow(A, B)=\)

If a line makes angles \(\alpha, \beta, \gamma\) and \(\delta\) with the four diagonals of a cube, then the value of \(\sin ^2 \alpha+\sin ^2 \beta+\sin ^2 \gamma+\sin ^2 \delta\) is

One bar magnet is in simple harmonic motion with time period T in an earth's magnetic field. If its mass is increased by 9 times the time period becomes

If \(\frac{1}{2 \times 4}+\frac{1}{4 \times 6}+\frac{1}{6 \times 8}+\ldots(n\) terms \()=\frac{k n}{n \times 1}\), then \(k\) is equal to