AP EAMCET · Chemistry · States of Matter
A gaseous mixture of 3 gases \(A, B\) and \(C\) has a pressure \(10 \mathrm{~atm}\). The total number of moles are 10. If partial pressure of gases \(A\) and \(B\) are \(3 \mathrm{~atm}\) and \(1 \mathrm{~atm}\) respectively and if molar mass of gas \(C\) is 2 . Calculate the weight of \(C\) in the mixture.
- A \(12 \mathrm{~g}\)
- B \(24 \mathrm{~g}\)
- C \(8 \mathrm{~g}\)
- D \(2 \mathrm{~g}\)
Answer & Solution
Correct Answer
(A) \(12 \mathrm{~g}\)
Step-by-step Solution
Detailed explanation
(i) \(p=p_A+p_B+p_C\) (Dalton's law) \((\because p=\text { total pressure, } p^{\prime}=\text { partial }\) pressure, \(\begin{aligned} & n=\text { number of moles }) \\ \Rightarrow & p_C=p-\left(p_A+p_B\right)=10-(3+1)=6 \mathrm{~atm} \end{aligned}\) (ii)…
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