AP EAMCET · Chemistry · States of Matter
\(A\) and \(B\) are ideal gases. The molecular weights of \(A\) and \(B\) are in the ratio of \(1: 4\). The pressure of a gas mixture containing equal weights of \(A\) and \(B\) is \(P\) atm. What is the partial pressure (in atm) of \(B\) in the mixture?
- A \(\frac{P}{5}\)
- B \(\frac{P}{2}\)
- C \(\frac{P}{2.5}\)
- D \(\frac{3 P}{4}\)
Answer & Solution
Correct Answer
(A) \(\frac{P}{5}\)
Step-by-step Solution
Detailed explanation
Mol. wt. ratio of \(A\) and \(B=1: 4\) \(\therefore\) mole ratio of \(A\) and \(B\), if equal weight of \(A\) and \(B\) are taken \(=4: 1\) \(\begin{aligned} \therefore \text { partial pressure of } B & =\frac{1}{(1+4)} \times P \\ & =\frac{P}{5} \end{aligned}\)
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