AP EAMCET · PHYSICS · Electrostatics
When a charge of \(20 \mathrm{C}\) is taken from one point to another separated by a distance of \(0.2 \mathrm{~m}\), work of \(2 \mathrm{~J}\) is required to be done.
What is the potential difference between the two points?
- A \(2 \times 10^{-2} \mathrm{~V}\)
- B \(4 \times 10^{-4} \mathrm{~V}\)
- C \(8 \mathrm{~V}\)
- D \(0.1 \mathrm{~V}\)
Answer & Solution
Correct Answer
(D) \(0.1 \mathrm{~V}\)
Step-by-step Solution
Detailed explanation
Charge, \(q=20 \mathrm{C}\) \[ \begin{aligned} d & =0.2 \mathrm{~m} \\ W & =2 \mathrm{~J} \end{aligned} \] Potential difference, \(V=\frac{W}{q}\) \[ =\frac{2}{20}=0.1 \mathrm{~V} \]
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