AP EAMCET · Chemistry · Some Basic Concepts of Chemistry
A \(40 \%\) by mass sucrose solution is heated till, it becomes \(50 \%\) by mass. Calculate the mass of water lost from \(100 \mathrm{~g}\) of the solution is
- A \(10 \mathrm{~g}\)
- B \(15 \mathrm{~g}\)
- C \(20 \mathrm{~g}\)
- D \(25 \mathrm{~g}\)
Answer & Solution
Correct Answer
(C) \(20 \mathrm{~g}\)
Step-by-step Solution
Detailed explanation
\(40 \%\) sucrose solution means it contains \(60 \%\) water. After heating, till \(50 \%\) by mass sucrose remains. Thus, \(\%\) water lost \(=\frac{0.4}{0.5} \times 100=80\) Water lost \(=100-80=20 \mathrm{~g}\) Hence, statement (c) is correct.
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