AP EAMCET · PHYSICS · Mechanical Properties of Solids
When a load of \(80 \mathrm{~N}\) is suspended from a string, its length is \(101 \mathrm{~mm}\). If a load of \(100 \mathrm{~N}\) is suspended, its length is \(102 \mathrm{~mm}\). If a load of \(160 \mathrm{~N}\) is suspended from it, then length of the string is (Assume the area of crosssection unchanged)
- A \(15.5\ cm\)
- B \(13.5\ cm\)
- C \(16.5\ cm\)
- D \(10.5\ cm\)
Answer & Solution
Correct Answer
(D) \(10.5\ cm\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text { Natural length }(l)=\frac{l_1 T_2-l_2 T_1}{T_2-T_1} \\ & =\frac{101 \times 100-102 \times 80}{(100-80)}\end{aligned}\)…
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