AP EAMCET · Chemistry · Chemical Equilibrium
For ammonia formation from constituent elements, the expression for \(\mathrm{K}_{\mathrm{C}}\) is
- A \(\mathrm{K}_{\mathrm{C}}=\frac{\left[\mathrm{NH}_3\right]^3}{\left[\mathrm{~N}_2\right]^3\left[\mathrm{H}_2\right]^3}\)
- B \(\mathrm{K}_{\mathrm{C}}=\frac{\left[\mathrm{NH}_3\right]^2}{\left[\mathrm{~N}_2\right]\left[\mathrm{H}_2\right]^3}\)
- C \(\mathrm{K}_{\mathrm{C}}=\frac{\left[\mathrm{NH}_3\right]}{\left[\mathrm{N}_2\right]\left[\mathrm{H}_2\right]}\)
- D \(\mathrm{K}_{\mathrm{C}}=\left[\mathrm{NH}_3\right]^2\)
Answer & Solution
Correct Answer
(B) \(\mathrm{K}_{\mathrm{C}}=\frac{\left[\mathrm{NH}_3\right]^2}{\left[\mathrm{~N}_2\right]\left[\mathrm{H}_2\right]^3}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{N}_2+3 \mathrm{H}_2 \rightarrow 2 \mathrm{NH}_3 ; \mathrm{K}_{\mathrm{c}}=\frac{\left[\mathrm{NH}_3\right]^2}{\left[\mathrm{~N}_2\right]\left[\mathrm{H}_2\right]^3}\)
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