AP EAMCET · Chemistry · Redox Reactions
\(2 \mathrm{Cu}_2 \mathrm{O}(s)+\mathrm{Cu}_2 \mathrm{~S}(s) \longrightarrow 6 \mathrm{Cu}(s)+\mathrm{SO}_2(g)\)
the oxidant and reductant respectively in the above reaction are
- A oxide of \(\mathrm{Cu}_2 \mathrm{O}\) and sulphide of \(\mathrm{Cu}_2 \mathrm{~S}\)
- B sulphide of \(\mathrm{Cu}_2 \mathrm{~S}\) and oxide of \(\mathrm{Cu}_2 \mathrm{O}\)
- C \(\mathrm{Cu}(\mathrm{I})\) of \(\mathrm{Cu}_2 \mathrm{O}, \mathrm{Cu}_2 \mathrm{~S}\) and sulphide of \(\mathrm{Cu}_2 \mathrm{~S}\)
- D \(\mathrm{Cu}(\mathrm{I})\) of \(\mathrm{Cu}_2 \mathrm{~S}, \mathrm{Cu}(\mathrm{I})\) of \(\mathrm{Cu}_2 \mathrm{O}\)
Answer & Solution
Correct Answer
(C) \(\mathrm{Cu}(\mathrm{I})\) of \(\mathrm{Cu}_2 \mathrm{O}, \mathrm{Cu}_2 \mathrm{~S}\) and sulphide of \(\mathrm{Cu}_2 \mathrm{~S}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{Cu}(\mathrm{I})\) of \(\mathrm{Cu}_2 \mathrm{O}(s)\) and \(\mathrm{Cu}_2 \mathrm{~S}(s)\) undergoes reduction to form \(\mathrm{Cu}(s)\) while sulphide of \(\mathrm{Cu}_2 \mathrm{~S}\) undergoes oxidation to form \(\mathrm{SO}_2(\mathrm{~g})\). Thus,…
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