AP EAMCET · Chemistry · Solutions
\(12.25 \mathrm{~g}\) of \(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CHClCOOH}\) is added to \(250 \mathrm{~g}\) of water to make a solution. If the dissociation constant of above acid is \(1.44 \times 10^{-3}\), the depression in freezing point of water in \({ }^{\circ} \mathrm{C}\) is \(\left(K_f\right.\) for water is \(\left.1.86 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\right)\)
- A 0.789
- B 0.394
- C 1.183
- D 0.592
Answer & Solution
Correct Answer
(A) 0.789
Step-by-step Solution
Detailed explanation
Step I Calculation of degree of dissociation Molar concentration of solution…
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