AP EAMCET · Chemistry · Ionic Equilibrium
At \(25^{\circ} \mathrm{C}\), the percentage of ionization of ' \(x\) ' M acetic acid is 4.242. What is the value of \(x ?\left(\mathrm{~K}_{\mathrm{a}}=1.8 \times 10^{-5}\right)\)
- A 0.05
- B 0.04
- C 0.02
- D 0.01
Answer & Solution
Correct Answer
(D) 0.01
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