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JEE Mains · Maths · STD 11 - 4.1 complex nubers

माना \(A =\left\{\theta \in\left(-\frac{\pi}{2}, \pi\right): \frac{3+2 i \sin \theta}{1-2 i \sin \theta}\right.\) मात्र काल्पनिक है \(\}\) तो \(A\) के अवयवों का योग है-

  1. A \(\frac{{5\pi }}{6}\)
  2. B \(\pi\)
  3. C \(\frac{{3\pi }}{4}\)
  4. D \(\frac{{2\pi }}{3}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{{2\pi }}{3}\)

Step-by-step Solution

Detailed explanation

\(z=\frac{3+2 i \sin \theta}{1-2 i \sin \theta} \) \(\times \frac{1+2 i \sin \theta}{1+2 i \sin \theta}\) \(z=\frac{\left(3-4 \sin ^{2} \theta\right)+8 i \sin \theta}{1+4 \sin ^{2} \theta}\) For purely imaginary real part should be zero. i.e. \(3-4 \sin ^{2} \theta=0\) ie.…
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