ExamBro
ExamBro
JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics

निम्नलिखित अभिक्रिया की बल गतिकी के अध्ययन के दौरान नीचे सारणी में दिये गये परिणाम प्राप्त हुए - \(2 A + B \longrightarrow C + D\)
प्रयोग \([ A ] / molL ^{-1}\) \([ B ] / molL ^{-1}\) प्रारंभिक दर \(/molL\) \(^{-1}\) \(\min ^{-1}\)
\(I\) \(0.1\) \(0.1\) \(6.00 \times 10^{-3}\)
\(II\) \(0.1\) \(0.2\) \(2.40 \times 10^{-2}\)
\(III\) \(0.2\) \(0.1\) \(1.20 \times 10^{-2}\)
\(IV\) \(X\) \(0.2\) \(7.20 \times 10^{-2}\)
\(V\) \(0.3\) \(Y\) \(2.88 \times 10^{-1}\)
दी गई सारणी में \(X\) तथा \(Y\) क्रमश : है 

  1. A \(0.3,0.4\)
  2. B \(0.4,0.3\)
  3. C \(0.4,0.4\)
  4. D \(0.3,0.3\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(0.3,0.4\)

Step-by-step Solution

Detailed explanation

From rate law \(= K [ A ]^{ x }[ B ]^{ y }\) \(6 \times 10^{-3}= K (0.1)^{ x }(0.1)^{ y }\)\(.....(1)\) \(2.4 \times 10^{-2}= K (0.1)^{ x }(0.2)^{ y } \ldots \ldots(2)\) \(1.2 \times 10^{-2}= K (0.2)^{ x }(0.1)^{ y }\)\(......(3)\) \((3) \div(1) \Rightarrow x=1\)…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app