केवल ग्लाइसीन \(\left( C _2 H _5 NO _2\right)\) रखने वाले प्रोटीन के \(2.5\) ग्राम को \(500\,mL\) विलयन बनाने के लिए जल में घोला गया है। \(300 K\) पर इस विलयन का परासरण दाब \(5.03 \times 10^{-3}\,bar\) पाया गया। प्रोटीन में उपस्थित ग्लाइसीन इकाईयों की संख्या \(.................\) है। (दिया है : \(R =0.083\,L\,bar\,K ^{-1}\,mol ^{-1}\) )

A \(120\)
B \(330\)
C \(450\)
D \(903\)

Verified Solution

Answer & Solution

Correct Answer

(B) \(330\)

Step-by-step Solution

Detailed explanation

\(\pi= CRT\) \(5.03 \times 10^{-3}= C \times 0.083 \times 300\) \(C =0.202 \times 10^{-3}\, M\) Moles of protein \(=0.202 \times 10^{-3} \times 0.5\) \(=10^{-4} \times 1.01\) \(1.01 \times 10^{-4}=\frac{2.5}{ M }\) \(M (\) molar mass of protein \()=24752\) \(\therefore\) No. of…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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