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JEE Mains · Maths · STD 12 - 9. differential equations

જો \(x \geq 0\) માટે \(y=y(x)\) એ વિકલ સમીકરણ \((\mathrm{x}+1) \mathrm{d} \mathrm{y}=\left((\mathrm{x}+1)^{2}+\mathrm{y}-3\right) \mathrm{d} \mathrm{x}, \mathrm{y}(2)=0\) નો ઉકેલ હોય તો \(y(3)\) મેળવો.

  1. A \(9\)
  2. B \(1\)
  3. C \(7\)
  4. D \(3\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(3\)

Step-by-step Solution

Detailed explanation

\((\mathrm{x}+1) \mathrm{d} \mathrm{y}-\mathrm{ydx}=\left((\mathrm{x}+1)^{2}-3\right) \mathrm{d} \mathrm{x}\) \(\Rightarrow \quad \frac{(\mathrm{x}+1) \mathrm{d} \mathrm{y}-\mathrm{ydx}}{(\mathrm{x}+1)^{2}}=\left(1-\frac{3}{(\mathrm{x}+1)^{2}}\right) \mathrm{dx}\)…
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