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JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola

ધારો કે \(\mathrm{P}(\alpha, \beta)\) એ પરવલય \(\mathrm{y}^2=4 \mathrm{x}\) પરનું એક બિંદુ છે. જો \(\mathrm{P}\) પરવલય \(x^2=8 y\) ની જીવા પર પણ આવેલું છે જેનું મધ્યબિંદુ \(\left(1, \frac{5}{4}\right)\) છે. તો \((\alpha-28)(\beta-8)\) = ...........

  1. A \(123\)
  2. B \(451\)
  3. C \(192\)
  4. D \(125\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(192\)

Step-by-step Solution

Detailed explanation

Parabola is \(x^2=8 y\) Chord with mid point \(\left(\mathrm{x}_1, \mathrm{y}_1\right)\) is \(\mathrm{T}=\mathrm{S}_1\) \( \therefore \mathrm{xx}_1-4\left(\mathrm{y}_1 \mathrm{y}_1\right)=\mathrm{x}_1^2-8 \mathrm{y}_1\)…
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