WBJEE · Physics · Gravitation
Two particles of mass \(m_{1}\) and \(m_{2}\); approach each other due to their mutual gravitational attraction only. Then,
- A accelerations of both the particles are equal
- B acceleration of the particle of mass \(m_{1}\) is proportional to \(\overline{m_{1}}\)
- C acceleration of the particle of mass \(m_{1}\) is proportional to \(m_{2}\)
- D acceleration of the particle of mass \(m_{1}\) is inversely proportional to \(m_{1}\)
Answer & Solution
Correct Answer
(C) acceleration of the particle of mass \(m_{1}\) is proportional to \(m_{2}\)
Step-by-step Solution
Detailed explanation
The gravitational force acting between the two masses \(m_{1}\) and \(m_{2}\) is given by \[ F_{O}=\frac{G m_{1} m_{2}}{r^{2}} \] Force on mass \(m_{1}\). \[ F_{1}=\frac{G m_{1} m_{2}}{r^{2}}=m_{1} a_{1} \] where, \(a_{1}=\) acceleration…
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