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WBJEE · Physics · Nuclear Physics

The energy released by the fission of one uranium atom is \(200 \mathrm{MeV}\). The number of fissions per second required to produce \(3.2 \mathrm{~W}\) of power is (Take \(1 \mathrm{eV}=1.6 \times 10^{-19} \mathrm{~J}\) )

  1. A \(10^7\)
  2. B \(10^{10}\)
  3. C \(10^{15}\)
  4. D \(10^{11}\)
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Answer & Solution

Correct Answer

(D) \(10^{11}\)

Step-by-step Solution

Detailed explanation

Hints: \(u=200 \mathrm{MeV}=200 \times 10^6 \mathrm{eV}=200 \times 10^6 \times 1.6 \times 10^{-19} \mathrm{~J}\) \(\mathrm{E}=3.2 \mathrm{~J}\) No of fissions \(=\frac{3.2}{2 \times 1.6 \times 10^{-11}}=10^{11}\)
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