WBJEE · Physics · Magnetic Properties of Matter
Magnetic field intensity \(\mathrm{H}\) at the centre of a circular loop of radius \(\mathrm{r}\) carrying current \(\mathrm{I}\) e m.u is
- A r/I oersted
- B \(2 \pi \mathrm{I} / \mathrm{r}\) oersted
- C \(\mathrm{I} / 2 \pi \mathrm{r}\) oersted
- D \(2 \pi \mathrm{r} / \mathrm{I}\) oersted
Answer & Solution
Correct Answer
(B) \(2 \pi \mathrm{I} / \mathrm{r}\) oersted
Step-by-step Solution
Detailed explanation
\(H=\frac{\mu_0 I}{2 r}=\frac{\mu_0}{4 \pi} \times \frac{2 \pi I}{r}\) In e m.u system \(\frac{\mu_0}{4 \pi}=1\). So \(H=\frac{2 \pi I}{r}\)
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