WBJEE · Chemistry · Structure of Atom
If the given four electronic configurations.
(i) \(n=4, l=1\)
(ii) \(n=4, l=0\)
(iii) \(n=3, l=2\)
(iv) \(n=3, l=1\)
are arranged in order of increasing energy, then the order will be
- A (iv) \( < \) (ii) \( < \) (iii) \( < \) (i)
- B (ii) \( < (\) iv \() < (i) < (\) iii \()\)
- C (i) \( < \) (iii) \( < \) (ii) \( < \) (iv)
- D (iii) \( < \) (i) \( < \) (iv) \( < \) (ii)
Answer & Solution
Correct Answer
(A) (iv) \( < \) (ii) \( < \) (iii) \( < \) (i)
Step-by-step Solution
Detailed explanation
According to \((n+l)\) rule; (i) More be the sum of \((n+l)\) value, more be the energy. (ii) For same value of sum, more be the value of \(n\), more be the energy. For (i) \(n+l \rightarrow 4+1=5\) (ii) \(n+l \rightarrow 4+0=4\) (iii) \(n+l \rightarrow 3+2=5\) (iv)…
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