WBJEE · Physics · Work Power Energy
A block of mass \(m\) slides with speed \(v\) on a frictionless table towards another stationary block of mass \(m\). A massless spring with spring constant \(\mathrm{k}\) is attached to the second block as shown in figure. The maximum distance the spring gets compress through is
- A \(\sqrt{\frac{\mathrm{m}}{\mathrm{k}}} \mathrm{v}\)
- B \(\sqrt{\frac{m}{2 k}} v\)
- C \(\sqrt{\frac{\mathrm{k}}{\mathrm{m}}} \mathrm{v}\)
- D \(\sqrt{\frac{\mathrm{k}}{2 \mathrm{~m}}} \mathrm{v}\)
Answer & Solution
Correct Answer
(B) \(\sqrt{\frac{m}{2 k}} v\)
Step-by-step Solution
Detailed explanation
\(\frac{1}{2} \mathrm{kx}^{2}=\frac{1}{2} \times \frac{\mathrm{m} \times \mathrm{m}}{2 \mathrm{~m}} \mathrm{v}^{2} \Rightarrow \mathrm{x}=\sqrt{\frac{\mathrm{m}}{2 \mathrm{k}}} \mathrm{v}\)
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