WBJEE · Maths · Probability
Two dice are tossed once. The probability of getting an even number at the first die or a total of 8 is
- A \(\frac{1}{36}\)
- B \(\frac{3}{36}\)
- C \(\frac{11}{36}\)
- D None of these
Answer & Solution
Correct Answer
(D) None of these
Step-by-step Solution
Detailed explanation
Hints: \(A=\) getting even no on 1st dice \[ \mathrm{B}=\text { getting sum } 8 \] So \(|\mathrm{A}|=18 \quad|\mathrm{~B}|=5 \quad|\mathrm{~A} \cap \mathrm{B}|=3\) \[ \text { So } P(A \cup B)=\frac{18+5-3}{36}=\frac{20}{36} \text {} \]
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