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WBJEE · Maths · Definite Integration

The value of \(I=\int_{0}^{\frac{\pi}{4}}\left(\tan ^{n+1} x\right) d x\)
\(+\frac{1}{2} \int_{0}^{\frac{\pi}{2}} \tan ^{n+1}\left(\frac{x}{2}\right) d x\) is

  1. A \(\frac{1}{n}\)
  2. B \(\frac{n+2}{2 n+1}\)
  3. C \(\frac{2 n-1}{n}\)
  4. D \(\frac{2 n-3}{3 n-2}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{1}{n}\)

Step-by-step Solution

Detailed explanation

.Given. \(I=\int_{0}^{\pi / 4}\left(\tan ^{n+1} x\right) d x+\frac{1}{2} \int_{0}^{\pi / 2} \tan ^{n-1}\left(\frac{x}{2}\right) d x\) In second integral, putt \(=\frac{x}{2} \Rightarrow d x=2 d t\) \(\Rightarrow \quad\) Also, when \(x=0\) then \(t=0\) When \(x=\pi / 2,\) then…