WBJEE · Maths · Ellipse
The line \(y=x+\lambda\) is tangent to the ellipse \(2 x^{2}+3 y^{2}=1 .\) Then \(, \lambda\) is
- A -2
- B 1
- C \(\sqrt{\frac{5}{6}}\)
- D \(\sqrt{\frac{2}{3}}\)
Answer & Solution
Correct Answer
(C) \(\sqrt{\frac{5}{6}}\)
Step-by-step Solution
Detailed explanation
The equation of the line is \(y=x+\lambda\) On comparing it with \(y=m x+c,\) we get \[ m=1 \text { and } c=\lambda \] The equation of the ellipse is \[ 2 x^{2}+3 y^{2}=1 \] or…
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