WBJEE · Maths · Application of Derivatives
The acceleration of a particle starting from rest moving in a straight line with uniform acceleration is \(8 \mathrm{~m} / \mathrm{sec}^2\). The time taken by the particle to move the second metre is
- A \(\frac{\sqrt{2}-1}{2} \mathrm{sec}\)
- B \(\frac{\sqrt{2}+1}{2} \mathrm{sec}\)
- C \((1+\sqrt{2}) \mathrm{sec}\)
- D \((\sqrt{2}-1) \mathrm{sec}\)
Answer & Solution
Correct Answer
(A) \(\frac{\sqrt{2}-1}{2} \mathrm{sec}\)
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