WBJEE · Maths · Continuity and Differentiability
If the function
\(f(x)= \begin{cases}\frac{x^2-(A+2) x+A}{x-2} & \text { for } x \neq 2 \\ 2 & \text { for } x=2\end{cases}\)
is continuous at \(x=2\), then
- A \(\mathrm{A}=0\)
- B \(\mathrm{A}=1\)
- C \(\mathrm{A}=-1\)
- D \(\mathrm{A}=2\)
Answer & Solution
Correct Answer
(A) \(\mathrm{A}=0\)
Step-by-step Solution
Detailed explanation
Hints: \(\frac{4-(A+2) 2+A}{0}=\frac{-A}{0}\) Put \(\mathrm{A}=0\).
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