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WBJEE · Maths · Definite Integration

If \(\phi(t)=\left\{\begin{array}{l}1, \text { for } 0 \leq t < 1 \\ 0, \text { otherwise }\end{array},\right.\) then \(\int_{-3000}^{3000}\left(\sum_{r^{\prime}=2014}^{2016} \phi(t-r') \phi(t-2016)\right) d t\) is

  1. A a real number
  2. B 1
  3. C 0
  4. D does not exist
Verified Solution

Answer & Solution

Correct Answer

(B) 1

Step-by-step Solution

Detailed explanation

\(\int_{-3000}^{3000}\left(\sum_{r'=2014}^{2016} \phi\left(t-r^{\prime}\right) \phi(t-2016)\right) d t\) \(=\int_{-3000}^{3000}[\phi(t-2014) \phi(t-2016)+\phi(t-2015) \phi(t-2016) +\phi(t-2016) \phi(t-2016)] \mathrm{dt}\)…