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WBJEE · Maths · Differentiation

If a particle moves in a straight line according to the law \(x=a \sin (\sqrt{\lambda} t+b)\), then the particle will come to rest at two points whose distance is [symbols have their usual meaning]

  1. A a
  2. B \(\frac{a}{2}\)
  3. C 2a
  4. D 4a
Verified Solution

Answer & Solution

Correct Answer

(C) 2a

Step-by-step Solution

Detailed explanation

Hint : \(\frac{\mathrm{dx}}{\mathrm{dt}}=\mathrm{a} \cos (\sqrt{\lambda} \mathrm{t}+\mathrm{b}) \cdot \sqrt{\lambda}=0\left[\begin{array}{l}\text { at rest, } \\ \frac{\mathrm{dx}}{\mathrm{dt}}=0\end{array}\right] \Rightarrow \cos (\sqrt{\lambda} \mathrm{t}+\mathrm{b})=0\)…