WBJEE · Maths · Differentiation
If a particle moves in a straight line according to the law \(x=a \sin (\sqrt{\lambda} t+b)\), then the particle will come to rest at two points whose distance is [symbols have their usual meaning]
- A a
- B \(\frac{a}{2}\)
- C 2a
- D 4a
Answer & Solution
Correct Answer
(C) 2a
Step-by-step Solution
Detailed explanation
Hint : \(\frac{\mathrm{dx}}{\mathrm{dt}}=\mathrm{a} \cos (\sqrt{\lambda} \mathrm{t}+\mathrm{b}) \cdot \sqrt{\lambda}=0\left[\begin{array}{l}\text { at rest, } \\ \frac{\mathrm{dx}}{\mathrm{dt}}=0\end{array}\right] \Rightarrow \cos (\sqrt{\lambda} \mathrm{t}+\mathrm{b})=0\)…
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