WBJEE · Maths · Quadratic Equation
If \((2+i)\) and \((\sqrt{5}-2 i)\) are the roots of the equation \(\left(x^{2}+a x+b\right)\left(x^{2}+c x+d\right)=0\) where \(a, b, c\) and \(d\) are real constants, then product of all the roots of the equation is
- A 40
- B \(9 \sqrt{5}\)
- C 45
- D 35
Answer & Solution
Correct Answer
(C) 45
Step-by-step Solution
Detailed explanation
If one root of a quadratic equation is of the form \(a+i b,\) then other root will be \(a-i b\) So, all the roots are \(2 \pm 1, \sqrt{5} \pm 2 i\) \(\therefore\) Product of all the roots \(=(2+i)(2-i)(\sqrt{5}+2 i)(\sqrt{5}-2 i)\) \(=(4+1)(5+4)=5 \times 9=45\)
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