WBJEE · Maths · Circle
A straight line meets the co-ordinate axes at \(\mathrm{A}\) and \(\mathrm{B}\). A circle is circumscribed about the triangle \(\mathrm{OAB}, \mathrm{O}\) being the origin. If \(\mathrm{m}\) and \(\mathrm{n}\) are the distances of the tangent to the circle at the origin from the points \(\mathrm{A}\) and \(\mathrm{B}\) respectively, the diameter of the circle is
- A \(m(m+n)\)
- B \(m+n\)
- C \(n(m+n)\)
- D \(\frac{1}{2}(m+n)\)
Answer & Solution
Correct Answer
(B) \(m+n\)
Step-by-step Solution
Detailed explanation
Clearly, AB is one of diameter \(\because \mathrm{AM}\) and \(\mathrm{BN}\) are parallel and \(\angle \mathrm{BNO}=\angle \mathrm{AMO}=\pi / 2\) \(\therefore\) Points \(\mathrm{N}, \mathrm{O}\) and \(\mathrm{M}\) are collinear. \(\therefore \triangle \mathrm{BNMA}\) is a…
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