WBJEE · Maths · Differentiation
A missile is fired from the ground level rises \(x\) meters vertically upwards in \(t \sec\), where \(x=100 t-\frac{25}{2} t^2\). The maximum height reached is
- A \(100 \mathrm{~m}\)
- B \(300 \mathrm{~m}\)
- C \(200 \mathrm{~m}\)
- D \(125 \mathrm{~m}\)
Answer & Solution
Correct Answer
(C) \(200 \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
Hint : \(x=100 t-\frac{25}{2} t^2\) \(\frac{d x}{d t}=100-25 \mathrm{t}\) for maximum and minimum \(\frac{d x}{d t}=0 \Rightarrow t=4 \mathrm{sec}\) \(\frac{d^2 x}{d t^2}=-25 < 0\) \(\therefore\) at \(\mathrm{x}=4\) it will have maixmum height…
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